C语言实现求解无穷级数 S = 1 + 1/2 + 1/4 + 1/7 + 1/11 + ... 直至项小于 10^-6

#include <stdio.h>

int main() { double s = 1.0, term = 1.0; int i = 2, j = 3; while (term >= 1e-6) { term = 1.0 / j; s += term; i++; j = i * (i + 1) / 2 + 1; } printf('s = %.6f\n', s); return 0; }