C++ 判断学生是否恰好有一门课不及格

#include using namespace std;

int main() { int chinese, math; cin >> chinese >> math;

if (chinese < 60 && math >= 60) {
    cout << 1 << endl;
} else if (chinese >= 60 && math < 60) {
    cout << 1 << endl;
} else {
    cout << 0 << endl;
}

return 0;

}