Crypto Challenge: Weak Encryption Scheme Analysis
The code first pads the flag to a multiple of 16 bytes using PKCS7 padding. Then, it generates a random permutation of indices using the 's_box' function. This permutation is stored in 'S_BOX'.
The 'encrypt1' function then divides the padded flag into 16-byte blocks, and for each block, it swaps each byte with the byte at a fixed distance away (determined by 'j*7%BLOCK'). However, the function doesn't actually modify the original 'm' array, so it has no effect on the ciphertext.
The 'encrypt2' function applies the permutation in 'S_BOX' to the bytes of the input 'm'. This function is applied to the plaintext 'm' after 'encrypt1' finishes. The resulting ciphertext is stored in 'c' and printed along with 'S_BOX'.
Therefore, the encryption scheme consists of two steps:
- Swap bytes within each 16-byte block of plaintext using 'encrypt1' (which doesn't actually do anything).
- Permute the bytes of the plaintext using a fixed permutation in 'S_BOX' using 'encrypt2'.
This encryption scheme is very weak and can be easily broken. Since the permutation in 'S_BOX' is fixed and known, an attacker can simply apply the inverse permutation to the ciphertext to recover the plaintext. Additionally, the swapping done in 'encrypt1' is predictable and doesn't add any security.
原文地址: https://www.cveoy.top/t/topic/myCZ 著作权归作者所有。请勿转载和采集!