C# 代码实现斐波那契数列第 30 项

int n = 30;
int a = 1, b = 1, c = 0;
for (int i = 3; i <= n; i++)
{
    c = a + b;
    a = b;
    b = c;
}
Console.WriteLine('第{0}个数是{1}', n, c);

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