Python 贪吃蛇游戏代码：简单易懂，快速上手

很高兴能够为您提供一个简单的贪吃蛇游戏代码。以下代码使用了 Python 的 pygame 库，您可以轻松地复制、粘贴并运行它。

import pygame
import random

# 初始化游戏引擎
pygame.init()

# 创建游戏窗口
screen_width = 600
screen_height = 600
screen = pygame.display.set_mode((screen_width, screen_height))
pygame.display.set_caption('贪吃蛇')

# 定义颜色
black = (0, 0, 0)
white = (255, 255, 255)
red = (255, 0, 0)
green = (0, 255, 0)

# 定义贪吃蛇和食物的大小
snake_block_size = 10
food_block_size = 10

# 定义时钟对象
clock = pygame.time.Clock()

# 定义字体对象
font = pygame.font.SysFont(None, 25)

# 定义函数：绘制贪吃蛇
def draw_snake(snake_block_size, snake_list):
    for x in snake_list:
        pygame.draw.rect(screen, green, [x[0], x[1], snake_block_size, snake_block_size])

# 定义函数：显示消息
def message(msg, color):
    text = font.render(msg, True, color)
    screen.blit(text, [screen_width / 6, screen_height / 3])

# 定义函数：游戏循环
def game_loop():
    game_over = False
    game_close = False

    # 初始化贪吃蛇的位置和长度
    snake_list = []
    snake_length = 1
    snake_x = screen_width / 2
    snake_y = screen_height / 2
    snake_x_change = 0
    snake_y_change = 0

    # 初始化食物的位置
    food_x = round(random.randrange(0, screen_width - food_block_size) / 10.0) * 10.0
    food_y = round(random.randrange(0, screen_height - food_block_size) / 10.0) * 10.0

    while not game_over:
        while game_close == True:
            screen.fill(white)
            message('游戏结束，按 Q 退出，按 C 重新开始', red)
            pygame.display.update()

            # 监听键盘事件
            for event in pygame.event.get():
                if event.type == pygame.KEYDOWN:
                    if event.key == pygame.K_q:
                        game_over = True
                        game_close = False
                    if event.key == pygame.K_c:
                        game_loop()

        # 监听键盘事件
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                game_over = True
            if event.type == pygame.KEYDOWN:
                if event.key == pygame.K_LEFT:
                    snake_x_change = -snake_block_size
                    snake_y_change = 0
                elif event.key == pygame.K_RIGHT:
                    snake_x_change = snake_block_size
                    snake_y_change = 0
                elif event.key == pygame.K_UP:
                    snake_y_change = -snake_block_size
                    snake_x_change = 0
                elif event.key == pygame.K_DOWN:
                    snake_y_change = snake_block_size
                    snake_x_change = 0

        # 碰到边界，游戏结束
        if snake_x >= screen_width or snake_x < 0 or snake_y >= screen_height or snake_y < 0:
            game_close = True

        # 更新贪吃蛇的位置
        snake_x += snake_x_change
        snake_y += snake_y_change

        # 绘制游戏窗口
        screen.fill(white)
        pygame.draw.rect(screen, red, [food_x, food_y, food_block_size, food_block_size])
        snake_head = []
        snake_head.append(snake_x)
        snake_head.append(snake_y)
        snake_list.append(snake_head)
        if len(snake_list) > snake_length:
            del snake_list[0]

        # 碰到自己，游戏结束
        for x in snake_list[:-1]:
            if x == snake_head:
                game_close = True

        # 绘制贪吃蛇和食物
        draw_snake(snake_block_size, snake_list)
        pygame.display.update()

        # 贪吃蛇吃到食物
        if snake_x == food_x and snake_y == food_y:
            food_x = round(random.randrange(0, screen_width - food_block_size) / 10.0) * 10.0
            food_y = round(random.randrange(0, screen_height - food_block_size) / 10.0) * 10.0
            snake_length += 1

        # 设置游戏速度
        clock.tick(15)

    # 结束游戏
    pygame.quit()
    quit()

# 运行游戏循环
game_loop()

使用上述代码，您可以实现一个简单的贪吃蛇游戏。希望对您有所帮助。