Python 生成 9x9 矩阵，外围一圈为 0

以下是 Python 代码实现：

matrix = [[0 for j in range(9)] for i in range(9)]  # 生成一个 9x9 的全 0 矩阵

for i in range(9):
    for j in range(9):
        if i == 0 or j == 0 or i == 8 or j == 8:  # 判断是否在边界上
            matrix[i][j] = 0  # 边界赋值为 0

# 输出矩阵
for i in range(9):
    for j in range(9):
        print(matrix[i][j], end=' ')
    print()

输出结果为：

0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0