Python 热力图刻度线显示问题解决方法

Python 代码：热力图刻度线显示问题解决方法

import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
import seaborn as sns

tables = pd.read_csv('E:/ZhouYifan_Master/Wave Energy/2018/02/height_period_energy.csv')
# print(tables.shape)
# print(list(tables.columns))
# print(tables.head())
swhh = np.array(tables['swh_swanxzm_year'])
# print(swh.shape)
# print(swh)
tmm10 = np.array(tables['tmm10_swanxzm_year'])
energy = np.array(tables['energy_swanxzm_year'])
index_swh = np.array(tables['index_swh'])
index_tmm10 = np.array(tables['index_tmm10'])
T_segment = np.linspace(0, 15, 16)
H_segment = np.linspace(0, 5.5, 12)
count_HT = np.zeros((len(H_segment), len(T_segment)))
color_J = np.zeros((len(H_segment), len(T_segment)))
T_segment = np.linspace(0, 16, 17)
H_plot = np.linspace(0, 11, 12)
ro = 1030
g = 9.8
A = 64 * np.pi / (ro * g * g)
x_plot = np.linspace(0, 16, 1601)
y_plot = np.linspace(0, 12, 1201)
def f(x, y):
    return x * (6 - 0.5 * y) * (6 - 0.5 * y) / A
X, Y = np.meshgrid(x_plot, y_plot)
Z = f(X, Y)
for i in range(len(swh)):
    count_HT[index_swh[i] - 1, index_tmm10[i] - 1] = count_HT[index_swh[i] - 1, index_tmm10[i] - 1] + 1
    color_J[index_swh[i] - 1, index_tmm10[i] - 1] = count_HT[index_swh[i] - 1, index_tmm10[i] - 1] + energy[i]

count_HT = np.flip(count_HT, axis=0)
color_J = np.flip(color_J, axis=0)
mask = np.zeros_like(count_HT)
mask[np.where(count_HT == 0)] = True

sns.set(font='Times New Roman', font_scale=4.5)
fig = plt.figure(figsize=(54, 36))
sns_plot = sns.heatmap(color_J, mask=mask, cmap='OrRd', annot=count_HT, fmt='.0f', annot_kws={'size': 50, 'weight': 'bold'}, square=False)
sns_plot.tick_params(direction='out', length=600, width=20, color='r')
plt.show()

热力图刻度线无法显示的解决方法

如果热力图刻度线不能显示，可以尝试以下方法：

调整 tick_params 函数参数：
- 将 length 和 width 调小，例如 length=200, width=10
- 将 color 改为黑色，例如 color='k'

使用其他绘图库：

尝试使用 matplotlib 库绘制热力图，例如：

plt.imshow(color_J, cmap='OrRd', interpolation='nearest')
plt.colorbar()
plt.show()

通过以上方法，您可以尝试解决热力图刻度线无法显示的问题。

注意： 不同的方法可能需要不同的参数调整，请根据实际情况进行尝试。