Python3 处理 WMV 视频时报 'need more than 1 value to unpack' 错误的解决方法/n/n在使用 Python3 处理 WMV 视频时,可能会遇到 'need more than 1 value to unpack' 错误。这是因为在多音轨情况下,音频信息不能被正确地解析。/n/n以下代码展示了如何修正代码以正确解析多音轨视频的音频信息:/n/npython/nimport os/nimport re/nimport subprocess/nimport openpyxl/nimport math/nfrom openpyxl.styles import Font, PatternFill, Alignment/n/n# 视频格式/nsupported_formats = [/n '.mp4',/n '.avi',/n '.mkv',/n '.wmv',/n '.mov',/n '.flv',/n '.m2ts',/n '.ts',/n '.rm',/n '.rmvb',/n '.vob',/n '.3gp',/n '.webm',/n '.hdmov',/n '.mp4v',/n '.mpv4',/n '.divx',/n '.xvid',/n '.f4v',/n '.mpeg',/n '.asf',/n '.asx',/n '.m2t',/n]/n/n# 视频文件夹/nvideo_folder = input('请输入文件夹路径:')/n/n# 输出Excel路径/nexcel_folder = '.'/n/n# 输出Excel文件名/nexcel_file = 'video_info.xlsx'/n/n# 正则表达式匹配码率数据中的空格/npattern = re.compile(r'(/d+)/s+(/d+)')/n/n# 创建Excel文件/nwb = openpyxl.Workbook()/nws = wb.active/nws.title = 'Video Info'/n/n# 获取视频文件列表(包括子目录)/nvideo_files = []/nfor root, dirs, files in os.walk(video_folder):/n for file in files:/n for format in supported_formats:/n if file.endswith(format):/n video_files.append(os.path.join(root, file))/n break/n/n# 锁定表头/nws.freeze_panes = 'A2'/n/n# 设置表头样式/nheader_font = Font(bold=True, color='800080') # 紫色/nheader_fill = PatternFill('solid', fgColor='C5E0B4')/nheader_alignment = Alignment(horizontal='center', vertical='center')/nheaders = [/n '文件名',/n '文件路径',/n '格式',/n '大小',/n '时长',/n '分辨率',/n '码率',/n '帧率',/n '音频码率',/n '音频采样率',/n '音频语言',/n '压缩比率',/n]/nfor col, header in enumerate(headers, start=1):/n cell = ws.cell(row=1, column=col, value=header)/n cell.font = header_font/n cell.fill = header_fill/n cell.alignment = header_alignment/n/n# 处理失败文件个数/nfailed_count = 0/n/n# 遍历所有视频文件/nsuccess_count = 0/nrow = 2 # 从第二行开始写入数据/nfor video_file in video_files:/n try:/n # 获取文件名/n file_name = os.path.basename(video_file)/n/n # 获取文件大小并进行单位换算/n size = os.path.getsize(video_file)/n if size < 1024:/n size_str = f'{size} B'/n elif size < 1024 * 1024:/n size_str = f'{size / 1024:.2f} KiB'/n elif size < 1024 * 1024 * 1024:/n size_str = f'{size / 1024 / 1024:.2f} MiB'/n else:/n size_str = f'{size / 1024 / 1024 / 1024:.2f} GiB'/n/n # 使用mediainfo获取视频信息 / 音频信息/n video_result = subprocess.run(/n [/n 'mediainfo',/n '--Inform=Video;%Format%|%Width%x%Height%|%BitRate/String%|%FrameRate%|%Duration/String3%',/n video_file,/n ],/n stdout=subprocess.PIPE,/n )/n video_output = video_result.stdout.decode().strip()/n audio_result = subprocess.run(/n [/n 'mediainfo',/n '--Inform=Audio;%BitRate/String%|%SamplingRate/String%|%Language/String%',/n video_file,/n ],/n stdout=subprocess.PIPE,/n )/n audio_output = audio_result.stdout.decode().strip()/n/n # 解析输出结果/n video_info = video_output.split('|')/n audio_info = audio_output.split('|')/n/n # 处理多音轨情况/n audio_bitrate = []/n audio_sampling_rate = []/n audio_lang = []/n for i in range(len(audio_info) // 3):/n audio_bitrate.append(audio_info[i * 3])/n audio_sampling_rate.append(audio_info[i * 3 + 1])/n audio_lang.append(audio_info[i * 3 + 2])/n/n # 时长取整/n duration = video_info[4].split('.')[0]/n h, m, s = duration.split(':')/n duration = f'{h}:{m}:{str(s).zfill(2)}'/n/n # 以分钟计算的时长 2/n duration_minutes = int(h) * 60 + int(m) + math.ceil(float(s)) / 60/n/n # 计算压缩比率/n ratio = round(duration_minutes / size * 1000000000, 2)/n/n # 使用正则表达式替换码率数据中第一个数字和第二个数字之间的空格/n bitrate = re.sub(pattern, r'/1/2', video_info[2])/n/n # 写入Excel文件/n ws.cell(row=row, column=1, value=file_name)/n ws.cell(row=row, column=2, value=os.path.dirname(video_file)) # 写入文件夹路径/n ws.cell(row=row, column=3, value=video_info[0])/n ws.cell(row=row, column=4, value=size_str)/n ws.cell(row=row, column=5, value=duration)/n ws.cell(row=row, column=6, value=video_info[1])/n ws.cell(row=row, column=7, value=bitrate)/n ws.cell(row=row, column=8, value=video_info[3])/n if audio_bitrate:/n ws.cell(row=row, column=9, value=' / '.join(audio_bitrate))/n if audio_sampling_rate:/n ws.cell(row=row, column=10, value=' / '.join(audio_sampling_rate))/n if audio_lang:/n ws.cell(row=row, column=11, value=' / '.join(audio_lang))/n ws.cell(row=row, column=12, value=ratio)/n # 打印进度/n print(f'已处理 {success_count+1}/{len(video_files)} 共计', end='/r')/n success_count += 1/n row += 1/n/n except Exception as e:/n # 处理失败,跳过并打印文件名和具体错误信息/n failed_count += 1/n print(f'处理文件 {file_name} 时失败:{e}')/n # 将失败的文件写入到err.txt/n with open('err.txt', 'a') as f:/n f.write(f'{file_name}/n')/n continue/n/n# 总计处理文件数/ntotal_count = len(video_files)/n/n# 调整L列左对齐/nl_col = ws['L']/nfor cell in l_col:/n cell.alignment = Alignment(horizontal='left') # 左对齐/n/n# 固定列宽/nfor col in ws.columns:/n col_letter = col[0].column_letter/n if col_letter not in ['C', 'H']: # 不固定格式、fps列的宽度/n ws.column_dimensions[col_letter].width = 11/n/n# 保存Excel文件/nif not os.path.exists(excel_folder):/n os.makedirs(excel_folder)/nexcel_file_path = os.path.join(excel_folder, excel_file)/nwb.save(excel_file_path)/n/n# 打印处理失败文件个数和总计处理文件数/nprint(/n f'已完成,处理成功 {success_count} 个文件,处理失败 {failed_count} 个文件,视频信息已保存到 {excel_file_path}'/n)/n/n/n代码修改说明:/n/n1. 在处理多音轨情况时,使用 for i in range(len(audio_info) // 3) 循环,以确保每个音频信息都能被正确解析。/n2. 在写入音频信息时,使用 if 语句判断是否有多个音轨,避免在只有一条音轨的情况下出现错误。/n/n注意:/n/n* 确保你的系统已安装 mediainfo 命令行工具。/n* 可以根据实际需要修改代码中的参数,如 supported_formatsvideo_folderexcel_folderexcel_file。/n/n希望这篇文章能帮助你解决 Python3 处理 WMV 视频时遇到的 'need more than 1 value to unpack' 错误。/n

Python3 处理 WMV 视频时报 'need more than 1 value to unpack' 错误的解决方法

原文地址: https://www.cveoy.top/t/topic/mFx1 著作权归作者所有。请勿转载和采集!

免费AI点我,无需注册和登录