Python 贪吃蛇游戏代码:简单易懂的实现
以下是一个简单的 Python 贪吃蛇游戏代码:
import pygame
import random
# 初始化Pygame
pygame.init()
# 游戏屏幕尺寸
screen_width = 480
screen_height = 480
# 创建游戏屏幕
screen = pygame.display.set_mode((screen_width, screen_height))
pygame.display.set_caption('贪吃蛇游戏')
# 定义颜色
white = (255, 255, 255)
black = (0, 0, 0)
red = (255, 0, 0)
# 定义贪吃蛇初始位置和大小
snake_block_size = 10
snake_speed = 15
# 定义字体
font_style = pygame.font.SysFont(None, 30)
# 显示得分
def show_score(score):
score_text = font_style.render('得分:' + str(score), True, white)
screen.blit(score_text, [0, 0])
# 绘制贪吃蛇
def draw_snake(snake_block_size, snake_list):
for x in snake_list:
pygame.draw.rect(screen, black, [x[0], x[1], snake_block_size, snake_block_size])
# 游戏结束
def game_over():
game_over_text = font_style.render('游戏结束!', True, white)
screen.blit(game_over_text, [screen_width/6, screen_height/3])
# 主函数
def gameLoop():
game_exit = False
game_over_flag = False
# 初始位置
x1 = screen_width/2
y1 = screen_height/2
# 初始移动方向
x1_change = 0
y1_change = 0
# 蛇身列表
snake_List = []
Length_of_snake = 1
# 食物初始位置
foodx = round(random.randrange(0, screen_width - snake_block_size) / 10.0) * 10.0
foody = round(random.randrange(0, screen_height - snake_block_size) / 10.0) * 10.0
clock = pygame.time.Clock()
# 游戏循环
while not game_exit:
while game_over_flag == True:
screen.fill(black)
game_over()
show_score(Length_of_snake - 1)
pygame.display.update()
# 如果按下Q键,退出游戏
for event in pygame.event.get():
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_q:
game_exit = True
game_over_flag = False
if event.key == pygame.K_c:
gameLoop()
# 处理事件
for event in pygame.event.get():
if event.type == pygame.QUIT:
game_exit = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
x1_change = -snake_block_size
y1_change = 0
elif event.key == pygame.K_RIGHT:
x1_change = snake_block_size
y1_change = 0
elif event.key == pygame.K_UP:
y1_change = -snake_block_size
x1_change = 0
elif event.key == pygame.K_DOWN:
y1_change = snake_block_size
x1_change = 0
# 判断是否碰到边缘
if x1 >= screen_width or x1 < 0 or y1 >= screen_height or y1 < 0:
game_over_flag = True
# 更新位置
x1 += x1_change
y1 += y1_change
# 游戏胜利
if Length_of_snake > 50:
game_over_text = font_style.render('你赢了!', True, white)
screen.blit(game_over_text, [screen_width/6, screen_height/3])
pygame.display.update()
pygame.time.wait(3000)
game_exit = True
# 绘制背景
screen.fill(black)
# 绘制食物
pygame.draw.rect(screen, red, [foodx, foody, snake_block_size, snake_block_size])
# 更新贪吃蛇列表
snake_Head = []
snake_Head.append(x1)
snake_Head.append(y1)
snake_List.append(snake_Head)
if len(snake_List) > Length_of_snake:
del snake_List[0]
# 判断是否吃到食物
for x in snake_List[:-1]:
if x == snake_Head:
game_over_flag = True
# 绘制贪吃蛇
draw_snake(snake_block_size, snake_List)
show_score(Length_of_snake - 1)
# 刷新屏幕
pygame.display.update()
# 判断是否吃到食物
if x1 == foodx and y1 == foody:
foodx = round(random.randrange(0, screen_width - snake_block_size) / 10.0) * 10.0
foody = round(random.randrange(0, screen_height - snake_block_size) / 10.0) * 10.0
Length_of_snake += 1
# 控制游戏速度
clock.tick(snake_speed)
# 退出Pygame
pygame.quit()
# 开始游戏
gameLoop()
原文地址: https://www.cveoy.top/t/topic/lXtO 著作权归作者所有。请勿转载和采集!