Here's the optimized code:

def multiply(n):
    return lambda x: n * x

multipliers = []
for x in range(5):
    multipliers.append(multiply(x))

Instead of creating a list of lambdas directly, we now have a list of functions (multipliers) that each return a lambda function. Each multiply(n) function generates and returns a lambda that multiplies n and x. This ensures that each lambda in the list has its own unique n value.

Python Code Optimization: Multiplying with Lambda Functions

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