基于状态转移矩阵的序列分析:PCA和PAC分析
from Bio import SeqIO
import numpy as np
import matplotlib.pyplot as plt
import os
# 读取fasta文件,计算状态转移矩阵
def calc_transition_matrix(fasta_file):
sequences = list(SeqIO.parse(fasta_file, "fasta"))
alphabet = list(set(''.join([str(seq.seq) for seq in sequences])))
states = len(alphabet)
matrix = np.zeros((states, states))
for seq in sequences:
seq_str = str(seq.seq)
for i in range(len(seq_str) - 1):
from_state = alphabet.index(seq_str[i])
to_state = alphabet.index(seq_str[i + 1])
matrix[from_state, to_state] += 1
return matrix
# 对矩阵进行z-score标准化
def standardize(matrix):
standardized_matrix = (matrix - np.mean(matrix, axis=0)) / np.std(matrix, axis=0)
return standardized_matrix
# 对标准化后的矩阵进行PCA分析
def pca(matrix):
cov = np.cov(matrix.T)
eig_vals, eig_vecs = np.linalg.eig(cov)
idx = np.argsort(eig_vals)[::-1]
eig_vecs = eig_vecs[:, idx]
projection = np.dot(matrix, eig_vecs)
return projection
# 绘制PAC图
def plot_pac(matrix):
cov = np.cov(matrix.T)
pac = np.zeros_like(cov)
for i in range(cov.shape[0]):
for j in range(cov.shape[1]):
pac[i, j] = cov[i, j] / np.sqrt(cov[i, i] * cov[j, j])
plt.imshow(pac, cmap='coolwarm')
plt.colorbar()
plt.show()
# 测试代码
if __name__ == "__main__":
# 获取文件夹中的所有fasta文件
fasta_folder = "./FASTA 文件"
fasta_files = [os.path.join(fasta_folder, f) for f in os.listdir(fasta_folder) if f.endswith(".fasta")]
# 对每个fasta文件进行状态转移矩阵的计算、标准化、PCA分析和PAC图绘制
for fasta_file in fasta_files:
# 读取fasta文件,计算状态转移矩阵
matrix = calc_transition_matrix(fasta_file)
print(matrix)
# 对矩阵进行标准化
standardized_matrix = standardize(matrix)
print(standardized_matrix)
# 对标准化后的矩阵进行PCA分析
pca_result = pca(standardized_matrix)
# 绘制PCA散点图
plt.scatter(pca_result[:, 0], pca_result[:, 1], label=fasta_file.split("/")[-1])
# 绘制PAC图
plot_pac(standardized_matrix)
plt.legend()
plt.show()
出现"No handles with labels found to put in legend"的原因是在绘制legend时没有指定label。需要在绘制散点图时指定label参数,如:
plt.scatter(pca_result[:, 0], pca_result[:, 1], label=fasta_file.split("/")[-1])
其中,fasta_file.split("/")[-1]用于获取fasta文件名,作为legend的label。
原文地址: https://www.cveoy.top/t/topic/lMSY 著作权归作者所有。请勿转载和采集!