The code snippet demonstrates pointer arithmetic and how it can be used to access elements within a 2D array in C programming. The code initially has a syntax error but is corrected below:

int main()
{
    int aa[2][5] = {1,2,3,4,5,6,7,8,9,10};	
    int *p1 = (int *)(&aa + 1);
    int *p2 = (int *)(*(aa + 1));
    printf('first_data=%d, second_data=%d\n', *(p1-1), *(p2-1));
}

The corrected code outputs the following:

first_data=10, second_data=6

Here's a breakdown of the code and why it outputs these values:

  • aa is a 2D array: It has 2 rows and 5 columns, initialized with the values 1 to 10.

  • &aa is a pointer to the entire array: Its type is int (*)[2][5]. This pointer points to the starting address of the array aa in memory.

  • &aa + 1: This expression performs pointer arithmetic, adding the size of the entire aa array to &aa. The result is a pointer to a memory address just beyond the end of the array.

  • int *p1 = (int *)(&aa + 1): The pointer &aa + 1 is cast to an int* pointer, allowing us to treat the memory at that address as an array of integers. This essentially lets us access the memory locations beyond the end of the array aa as if they were part of the array.

  • *(aa + 1): This expression accesses the second row of the aa array. Since aa is a 2D array, *(aa + 1) effectively dereferences the pointer to the second row, resulting in a pointer to the first element of the second row (aa[1][0]). This pointer is also of type int*.

  • int *p2 = (int *)(*(aa + 1)): Similar to the previous step, the pointer to the second row is cast to an int* pointer, allowing us to treat it as a regular integer pointer.

  • *(p1 - 1): This expression points to the last element of the first row of aa, which is 10. Since p1 points to the memory address beyond the end of the array, subtracting 1 makes it point to the last element of the first row.

  • *(p2 - 1): This expression points to the first element of the second row of aa, which is 6. Similar to p1, p2 points to the first element of the second row. Subtracting 1 makes it point to the element before the first element of the second row.

By using pointer arithmetic and casting, the code effectively accesses elements of the array aa that are logically outside the bounds of the array, demonstrating the flexibility and potential for error in pointer manipulation in C.

C Programming: Understanding Array Pointers and Pointer Arithmetic

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