8086汇编指令SUBB A, R5执行结果分析
( A )=0A7H, (R5)=68H, Cy =1,执行指令 SUBB A ,R5后 ( A )=[填空1] Cy =[填空2] Ac =[填空3] OV =[填空4] P =[填空5] 首先A不等于9FH和FFH内容:
( A )='FFH' Cy =1 Ac =0 OV =0 P =1 (因为'FFH'为负数,符号位为1,所以P为1)
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