D语言字符串转C语言char*类型高效方法:性能比较与优化

本文将探讨在D语言中将字符串转换为C语言char*类型的高效方法,并对不同方法的性能进行比较。同时,我们将介绍使用D语言内置的std.algorithm.replace函数优化字符串替换操作的示例代码,提升程序效率。

1. 核心代码实现与分析

import std.stdio;

import core.stdc.stdio:printf;
import core.stdc.string;
import core.stdc.stdlib : malloc, free;
import core.stdc.ctype:tolower;
import std:toUTFz;
import std.string:fromStringz,toStringz;
import std.datetime;
import std.conv:to;


/** 判断字符串是否以\0结束 **/
bool isStringEndsWithEmptyChar(string allStr)
{
    if(allStr[$-1] == '\0')
    {
        return true;
    }
    auto thePtr = allStr.ptr;
    if(thePtr[allStr.length]=='\0')
    {
        return true;
    }
    return false;
}
/**
  转为c语言char*类型
  1,最后一个字符是否为\0空字符,如果是则直接转为c语言的char*
  2,不是根据情况是否产生新的,比如判断是否是常量区域字符串
 **/
char* toCharPtrByUtf(string allStr,bool isCanWrite=false)
{
    auto thePtr = allStr.ptr;
    bool isHasEmpty = isStringEndsWithEmptyChar(allStr);
    if(!isCanWrite)
    {
        if(isHasEmpty)
        {
            return cast(char*)thePtr;
        }
        else
        {
            return toUTFz!(char*)(allStr);
        }
    }
    //不是指向常量数据区域的指针
    if (cast(ulong) thePtr >= 0x400000 && cast(ulong) thePtr <= 0x600000)
    {
        return toUTFz!(char*)(allStr);
    }

    if(isHasEmpty)
    {
        return cast(char*)thePtr;
    }
    else
    {
        return toUTFz!(char*)(allStr);
    }


}
/**
  转为c语言char*类型
  1,最后一个字符是否为\0空字符,如果是则直接转为c语言的char*
  2,总会复制一个信的字符串,利用toStringz
 **/
char* toCharPtr(string allStr,bool isCanWrite=false)
{
    auto thePtr = allStr.ptr;
    bool isHasEmpty = isStringEndsWithEmptyChar(allStr);
    if(!isCanWrite)
    {
        if(isHasEmpty)
        {
            return cast(char*)thePtr;
        }
        else
        {
            return cast(char*)(toStringz(allStr));
        }
    }
    //不是指向常量数据区域的指针
    if (cast(ulong) thePtr >= 0x400000 && cast(ulong) thePtr <= 0x600000)
    {
        return cast(char*)(toStringz(allStr));
    }

    if(isHasEmpty)
    {
        return cast(char*)thePtr;
    }
    else
    {
        return cast(char*)(toStringz(allStr));
    }
}
/**
  转为c语言const char*类型
 **/
const(char) * toConstCharPtrByUtf(string allStr)
{
    auto thePtr = allStr.ptr;
    bool isHasEmpty = isStringEndsWithEmptyChar(allStr);
    if(isHasEmpty)
    {
        return thePtr;
    }
    else
    {
        return toUTFz!(const(char) *)(allStr);
    }
}
/**
  转为c语言const char*类型
 **/
const(char) * toConstCharPtr(string allStr)
{
    auto thePtr = allStr.ptr;
    bool isHasEmpty = isStringEndsWithEmptyChar(allStr);
    if(isHasEmpty)
    {
        return thePtr;
    }
    else
    {
        return cast(const(char) *)(toStringz(allStr));
    }
}


// 判断两个字符是否相等,根据 isCaseSensitive 参数决定是否区分大小写
private bool charEqual(char a, char b, bool isCaseSensitive) @nogc nothrow
{
    if (isCaseSensitive)
    {
        return a == b;
    }
    else
    {
        return tolower(a) == tolower(b);
    }
}

// 在字符串 haystack 中查找第一次出现 needle 的位置,返回指向该位置的指针,如果找不到则返回 null
private char* strstrCase(char* haystack, const char* needle, bool isCaseSensitive) @nogc nothrow
{
    if (!haystack || !needle || !*needle)
    {
        return haystack;
    }

    size_t haystackLen = strlen(haystack);
    size_t needleLen = strlen(needle);

    if (needleLen > haystackLen)
    {
        return null;
    }

    if (isCaseSensitive)
    {
        return strstr(haystack, needle);
    }

    for (size_t i = 0; i <= haystackLen - needleLen; i++)
    {
        bool found = true;
        for (size_t j = 0; j < needleLen; j++)
        {
            if (!charEqual(haystack[i + j], needle[j], isCaseSensitive))
            {
                found = false;
                break;
            }
        }
        if (found)
        {
            return haystack + i;
        }
    }

    return null;
}

char* replaceCstr(const char* allStr, const char* searchStr, const char* replaceStr, bool isCaseSensitive=true) @nogc nothrow
{
    if (!allStr || !searchStr || !replaceStr || !*searchStr)
    {
        return cast(char*)allStr;
    }

    char* result = null;

    ulong searchStrLength = strlen(searchStr);
    ulong replaceStrLength = strlen(replaceStr);
    ulong count = 0;
    char* p = cast(char*)allStr;

    while ((p = strstrCase(p, searchStr, isCaseSensitive)) != null)
    {
        count++;
        p += searchStrLength;
    }

    if (count == 0)
    {
        return cast(char*)allStr;
    }

    ulong newStrLength = strlen(allStr) + count * (replaceStrLength - searchStrLength);
    result = cast(char*) malloc(newStrLength + 1);

    char* q = result;
    p = cast(char*)allStr;

    while (count-- > 0)
    {
        char* r = strstrCase(p, searchStr, isCaseSensitive);
        long length = r - p;

        memmove(q, p, length);
        q += length;

        memcpy(q, replaceStr, replaceStrLength);
        q += replaceStrLength;

        p = r + searchStrLength;
    }

    strcpy(q, p);

    return result;
}




void main()
{
    auto start = Clock.currTime();

    string str = 'hello, world!';
    const(char*) oldptr = toConstCharPtr(str);
    char* now = null;
    for (int ii = 0; ii < 10000000; ii++)
    {
        now = replaceCstr(oldptr,"o".ptr,"O".ptr);
        now = replaceCstr(oldptr,"l".ptr,"1".ptr);
        now = replaceCstr(oldptr,",".ptr,"".ptr);
        now = replaceCstr(oldptr,"!".ptr,"".ptr);
        //str = str.replaceString("o", "0").replaceString("l", "1").replaceString(",", "").replaceString("!", "");
    }
    if(oldptr!=now)
    {
        free(now);
    }

    auto end = Clock.currTime();
    writeln("D语言程序运行时间  :", end-start);

} 
replaceCstr函数实现效率比较低,请给出你能实现相同功能的最高效算法内容:可以考虑使用D语言内置的std.algorithm.replace函数,它可以在字符串中替换指定的子字符串。这个函数的实现效率比手写的replaceCstr函数要高很多。

下面是使用std.algorithm.replace实现的代码:

```d
import std.stdio;
import std.algorithm;
import std.datetime;

void main()
{
    auto start = Clock.currTime();

    string str = 'hello, world!';
    for (int ii = 0; ii < 10000000; ii++)
    {
        str = str.replace("o", "O").replace("l", "1").replace(",", "").replace("!", "");
    }

    auto end = Clock.currTime();
    writeln("D语言程序运行时间  :", end-start);
}
D语言字符串转C语言char*类型高效方法:性能比较与优化

原文地址: https://www.cveoy.top/t/topic/jomG 著作权归作者所有。请勿转载和采集!

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