ROS CPP 代码实现乌龟三角形编队
以下是可能的代码实现:
#include <ros/ros.h>
#include <geometry_msgs/Twist.h>
#include <turtlesim/Pose.h>
#include <cmath>
// 定义常量
const double PI = 3.14159265359;
const double SIDE_LENGTH = 1.0;
// 定义全局变量
ros::Publisher pubA, pubB, pubC;
turtlesim::Pose poseA, poseB, poseC;
// 计算两点之间的距离
double distance(double x1, double y1, double x2, double y2) {
return std::sqrt(std::pow(x1 - x2, 2) + std::pow(y1 - y2, 2));
}
// 计算两点之间的角度
double angle(double x1, double y1, double x2, double y2) {
return std::atan2(y2 - y1, x2 - x1);
}
// 控制A运动的回调函数
void moveCallback(const geometry_msgs::Twist::ConstPtr& msg) {
// 更新A的位置
double dt = 0.1; // 时间间隔
poseA.x += msg->linear.x * std::cos(poseA.theta) * dt;
poseA.y += msg->linear.x * std::sin(poseA.theta) * dt;
poseA.theta += msg->angular.z * dt;
// 发布A的位置
pubA.publish(poseA);
// 计算B和C应该在的位置
double angleBC = angle(poseB.x, poseB.y, poseC.x, poseC.y);
double xB = poseA.x + SIDE_LENGTH * std::cos(poseA.theta + PI / 3);
double yB = poseA.y + SIDE_LENGTH * std::sin(poseA.theta + PI / 3);
double xC = poseA.x + SIDE_LENGTH * std::cos(poseA.theta - PI / 3);
double yC = poseA.y + SIDE_LENGTH * std::sin(poseA.theta - PI / 3);
double xB_new = poseA.x + SIDE_LENGTH * std::cos(angleBC + PI / 3);
double yB_new = poseA.y + SIDE_LENGTH * std::sin(angleBC + PI / 3);
double xC_new = poseA.x + SIDE_LENGTH * std::cos(angleBC - PI / 3);
double yC_new = poseA.y + SIDE_LENGTH * std::sin(angleBC - PI / 3);
// 更新B和C的位置
poseB.x += msg->linear.x * (xB_new - xB) / distance(poseB.x, poseB.y, xB, yB);
poseB.y += msg->linear.x * (yB_new - yB) / distance(poseB.x, poseB.y, xB, yB);
poseC.x += msg->linear.x * (xC_new - xC) / distance(poseC.x, poseC.y, xC, yC);
poseC.y += msg->linear.x * (yC_new - yC) / distance(poseC.x, poseC.y, xC, yC);
// 发布B和C的位置
pubB.publish(poseB);
pubC.publish(poseC);
}
int main(int argc, char** argv) {
// 初始化ROS节点
ros::init(argc, argv, "turtle_triangle");
ros::NodeHandle nh;
// 创建三个乌龟的发布器
pubA = nh.advertise<turtlesim::Pose>("/turtle1/pose", 10);
pubB = nh.advertise<turtlesim::Pose>("/turtle2/pose", 10);
pubC = nh.advertise<turtlesim::Pose>("/turtle3/pose", 10);
// 订阅A的运动控制指令
ros::Subscriber sub = nh.subscribe("/turtle1/cmd_vel", 10, moveCallback);
// 初始化A、B、C的位置
poseA.x = 1.0;
poseA.y = 1.0;
poseA.theta = 0.0;
poseB.x = poseA.x + SIDE_LENGTH * std::cos(poseA.theta + PI / 3);
poseB.y = poseA.y + SIDE_LENGTH * std::sin(poseA.theta + PI / 3);
poseB.theta = poseA.theta;
poseC.x = poseA.x + SIDE_LENGTH * std::cos(poseA.theta - PI / 3);
poseC.y = poseA.y + SIDE_LENGTH * std::sin(poseA.theta - PI / 3);
poseC.theta = poseA.theta;
// 循环发布A、B、C的位置,直到节点被关闭
ros::Rate rate(10);
while (ros::ok()) {
pubA.publish(poseA);
pubB.publish(poseB);
pubC.publish(poseC);
ros::spinOnce();
rate.sleep();
}
return 0;
}
解释一下代码的实现思路:
- 定义常量PI和SIDE_LENGTH,PI表示圆周率,SIDE_LENGTH表示三角形的边长。
- 定义全局变量pubA、pubB、pubC和poseA、poseB、poseC,分别表示三个乌龟的发布器和位置信息。
- 定义distance和angle函数,分别用于计算两点之间的距离和角度。
- 定义moveCallback函数,用于处理A的运动控制指令。首先更新A的位置,然后计算B和C应该在的位置,再根据当前位置和目标位置的距离和角度,更新B和C的位置。最后发布A、B、C的位置信息。
- 在main函数中,初始化ROS节点,创建三个乌龟的发布器,订阅A的运动控制指令,初始化A、B、C的位置,然后循环发布A、B、C的位置信息,直到节点被关闭。
原文地址: https://www.cveoy.top/t/topic/jo0c 著作权归作者所有。请勿转载和采集!