求解六位数谜题：个位移至首位，新数为旧数的四倍

#include using namespace std;

int main() { for (int i = 1; i <= 9; i++) { for (int j = 0; j <= 9; j++) { for (int k = 0; k <= 9; k++) { for (int l = 0; l <= 9; l++) { for (int m = 0; m <= 9; m++) { int oldNum = i * 100000 + j * 10000 + k * 1000 + l * 100 + m * 10 + 7; int newNum = 7 * 100000 + i * 10000 + j * 1000 + k * 100 + l * 10 + m; if (newNum == 4 * oldNum) { cout << oldNum << endl; return 0; } } } } } } return 0; }