#include <iostream>
#include <vector>
#include <cmath>
using namespace std;

int countMonsters(int n, int m, int k, vector<pair<int, int>>& torches, vector<pair<int, int>>& glowstones) {
    int count = 0;
    vector<vector<int>> grid(n, vector<int>(n, 0)); // 0: no light, 1: torch light, 2: glowstone light

    // Place torches
    for (const auto& torch : torches) {
        int x = torch.first;
        int y = torch.second;
        grid[x-1][y-1] = 1;

        // Light up surrounding cells
        for (int i = max(0, x-2); i <= min(n-1, x); i++) {
            for (int j = max(0, y-2); j <= min(n-1, y); j++) {
                if (grid[i][j] == 0) {
                    grid[i][j] = 1;
                }
            }
        }
    }

    // Place glowstones
    for (const auto& glowstone : glowstones) {
        int x = glowstone.first;
        int y = glowstone.second;
        grid[x-1][y-1] = 2;
    }

    // Count cells with no light
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            if (grid[i][j] == 0) {
                count++;
            }
        }
    }

    return count;
}

int main() {
    int n, m, k;
    cin >> n >> m >> k;

    vector<pair<int, int>> torches(m);
    for (int i = 0; i < m; i++) {
        int x, y;
        cin >> x >> y;
        torches[i] = make_pair(x, y);
    }

    vector<pair<int, int>> glowstones(k);
    for (int i = 0; i < k; i++) {
        int x, y;
        cin >> x >> y;
        glowstones[i] = make_pair(x, y);
    }

    int result = countMonsters(n, m, k, torches, glowstones);
    cout << result << endl;

    return 0;
}
话说有一天 linyorson 在我的世界开了一个 �×�n×n 的方阵现在他有 �m 个火把和 �k 个萤石分别放在 �1�1∼����x 1 y 1 ∼x m y m 和 �1�1∼����o 1 p 1 ∼o k p k 的位置没有光并且没放东西的地方会生成怪物。请问在这个方阵中有几个点会生成怪物?PS 火把的照亮范围是: 暗暗 光 暗暗 暗光 光 光暗

原文地址: https://www.cveoy.top/t/topic/jgkm 著作权归作者所有。请勿转载和采集!

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