已知附合导线的六个点分别为MACDBN且同时已知TAM＝330°TBN＝30°导线中各转折角的观测值为βMAC= 120°0004 βACD= 180°0002 βCDB=180°0001βDBN= 120°0002;求各转折角的改正数

首先将给定的角度转换为度数形式： βMAC = 120°00'04" = 120.0011° βACD = 180°00'02" = 180.0006° βCDB = 180°00'01" = 180.0003° βDBN = 120°00'02" = 120.0006°

然后计算各转折角的改正数： αMAC = βMAC - 180° = 120.0011° - 180° = -59.9989° αACD = βACD - 180° = 180.0006° - 180° = 0.0006° αCDB = βCDB - 180° = 180.0003° - 180° = 0.0003° αDBN = βDBN - 180° = 120.0006° - 180° = -59.9994°

所以各转折角的改正数为： αMAC = -59.9989° αACD = 0.0006° αCDB = 0.0003° αDBN = -59.9994°