描述某医院想统计一下某项疾病的获得与否与年龄是否有关需要对以前的诊断记录进行整理按照0-18、19-35、36-60、61以上含61四个年龄段统计的患病人数占总患病人数的比例。输入描述共2行第一行为过往病人的数目n0n≤100第二行为每个病人患病时的年龄。输出描述按照0-18、19-35、36-60、61以上含61四个年龄段输出该段患病人数占总患病人数的比例以百分比的形式输出精确到小数点后两位。每

#include <iostream>
#include <iomanip>
#include <vector>

using namespace std;

int main() {
    int n;
    cin >> n;
    
    vector<int> ages(n);
    for (int i = 0; i < n; i++) {
        cin >> ages[i];
    }
    
    int count1 = 0, count2 = 0, count3 = 0, count4 = 0;
    for (int i = 0; i < n; i++) {
        if (ages[i] >= 0 && ages[i] <= 18) {
            count1++;
        } else if (ages[i] >= 19 && ages[i] <= 35) {
            count2++;
        } else if (ages[i] >= 36 && ages[i] <= 60) {
            count3++;
        } else {
            count4++;
        }
    }
    
    double ratio1 = (double)count1 / n * 100;
    double ratio2 = (double)count2 / n * 100;
    double ratio3 = (double)count3 / n * 100;
    double ratio4 = (double)count4 / n * 100;
    
    cout << fixed << setprecision(2) << ratio1 << "%" << endl;
    cout << fixed << setprecision(2) << ratio2 << "%" << endl;
    cout << fixed << setprecision(2) << ratio3 << "%" << endl;
    cout << fixed << setprecision(2) << ratio4 << "%" << endl;
    
    return 0;
}