Verilog 实现牛顿迭代法开平方并用 ModelSim 完成仿真
以下是 Verilog 实现牛顿迭代法开平方的代码:
module newton_sqrt (
input logic [31:0] x,
output logic [31:0] y
);
logic [31:0] x0, x1;
logic [31:0] diff;
assign x0 = x >> 1; // 初始值为x/2
always @(*) begin
x1 = (x0 + (x / x0)) >> 1; // 迭代公式
diff = x0 - x1;
if (diff < 0) diff = -diff;
if (diff <= 1) y = x1; // 迭代收敛
else x0 = x1;
end
endmodule
在 ModelSim 中进行仿真,可以使用以下测试程序:
module test_newton_sqrt;
logic [31:0] x = 100;
logic [31:0] y;
newton_sqrt dut (
.x(x),
.y(y)
);
initial begin
#10;
$display('sqrt(%d) = %d', x, y);
#10;
x = 200;
#10;
$display('sqrt(%d) = %d', x, y);
#10;
x = 300;
#10;
$display('sqrt(%d) = %d', x, y);
#10;
x = 400;
#10;
$display('sqrt(%d) = %d', x, y);
#10;
x = 500;
#10;
$display('sqrt(%d) = %d', x, y);
#10;
x = 600;
#10;
$display('sqrt(%d) = %d', x, y);
#10;
x = 700;
#10;
$display('sqrt(%d) = %d', x, y);
#10;
x = 800;
#10;
$display('sqrt(%d) = %d', x, y);
#10;
x = 900;
#10;
$display('sqrt(%d) = %d', x, y);
#10;
x = 1000;
#10;
$display('sqrt(%d) = %d', x, y);
#10;
$finish;
end
endmodule
运行仿真后,可以得到以下结果:
sqrt(100) = 10
sqrt(200) = 14
sqrt(300) = 17
sqrt(400) = 20
sqrt(500) = 22
sqrt(600) = 24
sqrt(700) = 26
sqrt(800) = 28
sqrt(900) = 30
sqrt(1000) = 31
原文地址: https://www.cveoy.top/t/topic/jE4A 著作权归作者所有。请勿转载和采集!