Mendelian Inheritance: Yellow Smooth Pea Cross with Heterozygous Yellow Wrinkled Pea

To determine the possible genotypes and phenotypes of the offspring, we need to apply Mendelian genetics principles.

The genotype of the homozygous yellow, homozygous smooth pea is YYSS (where Y represents the yellow allele and S represents the smooth allele). The genotype of the heterozygous yellow, homozygous wrinkled pea is Yyss (where y represents the green allele and s represents the wrinkled allele).

When these two parents are crossed, we can use a Punnett square to determine the possible genotypes and phenotypes of the offspring.

The Punnett square for this cross would look like:

  Y     Y
----------------

y | Yy Yy y | Yy Yy

S | YySs YySs s | YySs YySs

From the Punnett square, we can see that there are four possible genotypes: YySs, YySs, YySs, and YySs.

The possible phenotypes of the offspring can be determined by looking at the expression of the dominant alleles. In this case, yellow (Y) is dominant over green (y), and smooth (S) is dominant over wrinkled (s). Therefore, all the offspring will have yellow seeds (because they inherit at least one Y allele) and smooth seeds (because they inherit at least one S allele). So, the possible phenotypes of the offspring are yellow and smooth.

In summary, the possible genotypes of the offspring are YySs, YySs, YySs, and YySs, and the possible phenotypes are yellow and smooth.