帮我用java和Typescript设计一个游戏经验等级方法0到100级

下面是用Java和TypeScript分别实现游戏经验等级方法的示例代码：

Java代码：

public class GameLevel {
    public static int getLevel(int experience) {
        if (experience < 0 || experience > 100) {
            throw new IllegalArgumentException("Experience must be between 0 and 100");
        }
        
        if (experience >= 0 && experience <= 10) {
            return 0;
        } else if (experience >= 11 && experience <= 20) {
            return 1;
        } else if (experience >= 21 && experience <= 30) {
            return 2;
        } else if (experience >= 31 && experience <= 40) {
            return 3;
        } else if (experience >= 41 && experience <= 50) {
            return 4;
        } else if (experience >= 51 && experience <= 60) {
            return 5;
        } else if (experience >= 61 && experience <= 70) {
            return 6;
        } else if (experience >= 71 && experience <= 80) {
            return 7;
        } else if (experience >= 81 && experience <= 90) {
            return 8;
        } else {
            return 9;
        }
    }
}

TypeScript代码：

function getLevel(experience: number): number {
  if (experience < 0 || experience > 100) {
    throw new Error("Experience must be between 0 and 100");
  }
  
  if (experience >= 0 && experience <= 10) {
    return 0;
  } else if (experience >= 11 && experience <= 20) {
    return 1;
  } else if (experience >= 21 && experience <= 30) {
    return 2;
  } else if (experience >= 31 && experience <= 40) {
    return 3;
  } else if (experience >= 41 && experience <= 50) {
    return 4;
  } else if (experience >= 51 && experience <= 60) {
    return 5;
  } else if (experience >= 61 && experience <= 70) {
    return 6;
  } else if (experience >= 71 && experience <= 80) {
    return 7;
  } else if (experience >= 81 && experience <= 90) {
    return 8;
  } else {
    return 9;
  }
}

以上代码中，getLevel方法接收一个表示经验值的参数，并根据经验值的范围返回相应的等级。如果经验值小于0或大于100，会抛出一个IllegalArgumentException（Java）或Error（TypeScript）异常。在Java代码中，使用if-else语句来判断经验值所在的范围，并返回相应的等级。在TypeScript代码中，使用if-else语句和throw关键字来实现相同的逻辑