python 算式 TOTAL_NUM_STEPS_1st = 1522 TOTAL_NUM_STEPS_2nd = 1523 TOTAL_NUM_STEPS_3rd = 1524当numer 越接近符合 TOTAL_NUM_STEPS_1st 的时候 奖励第一好当numer 越接近符合 TOTAL_NUM_STEPS_2nd 的时候 奖励第二好当nume

您可以使用以下代码来计算numer与TOTAL_NUM_STEPS的差距，并根据差距大小给出奖励等级：

numer = 330

diff_1st = abs(numer - TOTAL_NUM_STEPS_1st)
diff_2nd = abs(numer - TOTAL_NUM_STEPS_2nd)
diff_3rd = abs(numer - TOTAL_NUM_STEPS_3rd)

if diff_1st < diff_2nd and diff_1st < diff_3rd:
    reward = "第一好"
elif diff_2nd < diff_1st and diff_2nd < diff_3rd:
    reward = "第二好"
else:
    reward = "第三好"

print(reward)

在上述代码中，我们首先计算numer与每个TOTAL_NUM_STEPS的差距（使用abs函数获取绝对值）。然后，通过比较差距大小来确定奖励等级。最后，打印出奖励等级。请注意，您需要在代码中定义TOTAL_NUM_STEPS_1st、TOTAL_NUM_STEPS_2nd和TOTAL_NUM_STEPS_3rd的值