java解压zip读取解压文件
以下是一个使用Java解压ZIP文件并读取解压文件的示例代码:
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
public class UnzipExample {
public static void main(String[] args) {
String zipFilePath = "path/to/your/zip/file.zip";
String destDirectory = "path/to/destination/directory";
try {
unzip(zipFilePath, destDirectory);
// 读取解压后的文件
File directory = new File(destDirectory);
File[] files = directory.listFiles();
if (files != null) {
for (File file : files) {
if (file.isFile()) {
// 处理解压后的文件
System.out.println("File: " + file.getName());
}
}
}
} catch (IOException e) {
e.printStackTrace();
}
}
public static void unzip(String zipFilePath, String destDirectory) throws IOException {
File destDir = new File(destDirectory);
if (!destDir.exists()) {
destDir.mkdir();
}
FileInputStream fis = new FileInputStream(zipFilePath);
ZipInputStream zipIn = new ZipInputStream(fis);
ZipEntry entry = zipIn.getNextEntry();
while (entry != null) {
String filePath = destDirectory + File.separator + entry.getName();
if (!entry.isDirectory()) {
extractFile(zipIn, filePath);
} else {
File dir = new File(filePath);
dir.mkdir();
}
zipIn.closeEntry();
entry = zipIn.getNextEntry();
}
zipIn.close();
fis.close();
}
private static void extractFile(ZipInputStream zipIn, String filePath) throws IOException {
BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(filePath));
byte[] bytesIn = new byte[4096];
int read;
while ((read = zipIn.read(bytesIn)) != -1) {
bos.write(bytesIn, 0, read);
}
bos.close();
}
}
请注意,上述代码中的zipFilePath和destDirectory需要根据实际情况进行替换,分别指定要解压的ZIP文件路径和解压后的目标目录路径。在解压后,您可以根据需要处理解压后的文件
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