用Java写一个Bukkit1201 当玩家从大型箱子的其中一个小箱子上贴上木牌 则箱子都无法打开
您可以使用以下代码来实现您的需求:
import org.bukkit.Bukkit;
import org.bukkit.Material;
import org.bukkit.block.Block;
import org.bukkit.block.BlockState;
import org.bukkit.block.Chest;
import org.bukkit.entity.Player;
import org.bukkit.event.EventHandler;
import org.bukkit.event.Listener;
import org.bukkit.event.block.Action;
import org.bukkit.event.player.PlayerInteractEvent;
import org.bukkit.event.inventory.InventoryOpenEvent;
import org.bukkit.event.inventory.InventoryType;
import org.bukkit.inventory.Inventory;
import org.bukkit.plugin.java.JavaPlugin;
public class ChestLockPlugin extends JavaPlugin implements Listener {
@Override
public void onEnable() {
Bukkit.getPluginManager().registerEvents(this, this);
}
@EventHandler
public void onPlayerInteract(PlayerInteractEvent event) {
Player player = event.getPlayer();
if (event.getAction() == Action.RIGHT_CLICK_BLOCK) {
Block block = event.getClickedBlock();
if (block.getType() == Material.CHEST || block.getType() == Material.TRAPPED_CHEST) {
Chest chest = (Chest) block.getState();
if (isChestLocked(chest)) {
event.setCancelled(true);
player.sendMessage("该箱子已被锁定!");
}
}
}
}
@EventHandler
public void onInventoryOpen(InventoryOpenEvent event) {
if (event.getInventory().getType() == InventoryType.CHEST) {
Chest chest = getChestFromInventory(event.getInventory());
if (chest != null && isChestLocked(chest)) {
event.setCancelled(true);
((Player) event.getPlayer()).sendMessage("该箱子已被锁定!");
}
}
}
private boolean isChestLocked(Chest chest) {
Inventory inventory = chest.getBlockInventory();
for (int i = 0; i < inventory.getSize(); i++) {
if (inventory.getItem(i) != null && inventory.getItem(i).getType() == Material.OAK_SIGN) {
return true;
}
}
return false;
}
private Chest getChestFromInventory(Inventory inventory) {
for (BlockState blockState : inventory.getViewers()) {
if (blockState instanceof Chest) {
return (Chest) blockState;
}
}
return null;
}
}
在这个插件中,我们使用了Bukkit的事件监听器来监听玩家与箱子的交互行为以及箱子的打开事件。当玩家右击一个箱子时,我们检查箱子是否被贴上了木牌,如果是,则取消玩家的交互行为并发送一条消息告知玩家该箱子已被锁定。当玩家尝试打开一个箱子时,我们同样检查箱子是否被贴上了木牌,如果是,则取消该事件并发送一条消息告知玩家该箱子已被锁定。
请注意,这只是一个简单的实现,您可能需要根据您的具体需求对代码进行修改和优化。
原文地址: https://www.cveoy.top/t/topic/ifXq 著作权归作者所有。请勿转载和采集!