int cmp = Integercompares1getSortOfAssessedAreas s2getSortOfAssessedAreas; if cmp != 0 return cmp; 按被考核者部门 cmp = Integercompares1getSortOfDeptAssessed s2getSo

可以优化这段代码如下：

int cmp = Integer.compare(s1.getSortOfAssessedAreas(), s2.getSortOfAssessedAreas());
if (cmp != 0) {
    return cmp;
}

cmp = Integer.compare(s1.getSortOfDeptAssessed(), s2.getSortOfDeptAssessed());
if (cmp != 0) {
    return cmp;
}

cmp = Integer.compare(s1.getSortOfAssessorAreas(), s2.getSortOfAssessorAreas());
if (cmp != 0) {
    return cmp;
}

cmp = Integer.compare(s1.getSortOfAssessorCompany(), s2.getSortOfAssessorCompany());
if (cmp != 0) {
    return cmp;
}

return s1.getExaminerDeptName().compareTo(s2.getExaminerDeptName());

这样，可以避免重复的代码，并且使代码更加简洁和易读