用python语言写一个脚本生成由012组成的所有3位数组合数字可以重复

可以使用嵌套循环来生成所有的3位数组合。以下是一个示例脚本：

def generate_combinations():
    combinations = []
    digits = [0, 1, 2]
    
    for i in digits:
        for j in digits:
            for k in digits:
                combination = [i, j, k]
                combinations.append(combination)
    
    return combinations

all_combinations = generate_combinations()
for combination in all_combinations:
    print(combination)

输出结果将是：

[0, 0, 0]
[0, 0, 1]
[0, 0, 2]
[0, 1, 0]
[0, 1, 1]
[0, 1, 2]
[0, 2, 0]
[0, 2, 1]
[0, 2, 2]
[1, 0, 0]
[1, 0, 1]
[1, 0, 2]
[1, 1, 0]
[1, 1, 1]
[1, 1, 2]
[1, 2, 0]
[1, 2, 1]
[1, 2, 2]
[2, 0, 0]
[2, 0, 1]
[2, 0, 2]
[2, 1, 0]
[2, 1, 1]
[2, 1, 2]
[2, 2, 0]
[2, 2, 1]
[2, 2, 2]

这样就生成了所有由0、1、2组成的3位数组合