n = int(input())
nums = list(map(int, input().split()))

odd_nums = []
even_nums = []

for num in nums:
    if num % 2 == 0:
        even_nums.append(num)
    else:
        odd_nums.append(num)

print(" ".join(str(num) for num in odd_nums))
print(" ".join(str(num) for num in even_nums))
#include <iostream>
#include <vector>
using namespace std;

int main() {
    int n;
    cin >> n;
    vector<int> nums(n);
    for (int i = 0; i < n; i++) {
        cin >> nums[i];
    }

    vector<int> odd_nums;
    vector<int> even_nums;

    for (int num : nums) {
        if (num % 2 == 0) {
            even_nums.push_back(num);
        } else {
            odd_nums.push_back(num);
        }
    }

    for (int num : odd_nums) {
        cout << num << " ";
    }
    cout << endl;
    for (int num : even_nums) {
        cout << num << " ";
    }
    cout << endl;

    return 0;
}
``
描述输入n个整数将其中的奇数和偶数分别显示出来1 n 30输入描述第一行:一个整数n。第二行:n个空格隔开的整数。输出描述第一行:若干个奇数。第二行:若干个偶数。每个数前面都有一个空格用例输入 1 1021 12 33 43 59 68 77 18 19 40用例输出 1 21 33 43 59 77 1912 68 18 40c++

原文地址: https://www.cveoy.top/t/topic/iEI3 著作权归作者所有。请勿转载和采集!

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