printfhhx 1234&127 输出结果为 为什么

The output of the statement printf("%hhx", 1234&127) would be 42.

In this statement, 1234 and 127 are two operands being operated by the bitwise AND operator &. The bitwise AND operation compares the corresponding bits of the two operands and returns a new value where each bit is set if and only if the corresponding bits of both operands are set.

In binary representation, 1234 is 0100 1101 0010 and 127 is 0000 0111. Performing the bitwise AND operation on these two numbers would result in 0000 0100, which is 4 in decimal.

The printf() statement is using the %hhx format specifier to print the result in hexadecimal format. The decimal value 4 is equivalent to 0x4 in hexadecimal. Therefore, the output of the statement would be 4 in hexadecimal, which is 42 in decimal