Use of overloaded operator == is ambiguous with operand types cocos2dextensionCCSafeObjectcocos2dNode and cocos2dextensionCCSafeObjectcocos2dNode

The error message "Use of overloaded operator '==' is ambiguous" typically occurs when there are multiple overloaded versions of the '==' operator that can be applied to the operands. In this case, the operands are of type 'cocos2d::extension::CCSafeObjectcocos2d::Node', and the compiler is unable to determine which version of the '==' operator to use.

To resolve this issue, you can explicitly define the '==' operator for the 'cocos2d::extension::CCSafeObjectcocos2d::Node' class, or you can use a different method to compare the objects.

Here is an example of how you can define the '==' operator for the 'cocos2d::extension::CCSafeObjectcocos2d::Node' class:

namespace cocos2d {
    namespace extension {
        template<typename T>
        bool operator==(const CCSafeObject<T>& obj1, const CCSafeObject<T>& obj2) {
            // Your comparison logic goes here
            return obj1.get() == obj2.get();
        }
    }
}

Alternatively, you can use a different comparison method, such as comparing the underlying pointers directly:

cocos2d::extension::CCSafeObject<cocos2d::Node> obj1;
cocos2d::extension::CCSafeObject<cocos2d::Node> obj2;

if (obj1.get() == obj2.get()) {
    // Objects are equal
} else {
    // Objects are not equal
}

By explicitly defining the '==' operator or using a different comparison method, you can resolve the ambiguity and avoid the error.