MATLAB代码如下:

% 海域尺寸
length = 2; % 南北长2海里
width = 4; % 东西宽4海里

% 海水深度信息
center_depth = 110; % 海水深度为110m
slope = 1.5; % 坡度为1.5

% 多波束换能器参数
beam_width = 120; % 开角为120°

% 遗传算法参数
population_size = 100; % 种群大小
max_generation = 100; % 最大迭代次数

% 生成初始种群
population = generate_population(population_size, length, width);

% 遗传算法迭代
for generation = 1:max_generation
    % 计算适应度
    fitness = compute_fitness(population, center_depth, slope, beam_width);
    
    % 选择
    selected_population = selection(population, fitness);
    
    % 交叉
    new_population = crossover(selected_population, population_size);
    
    % 变异
    population = mutation(new_population);
end

% 获取最优解
best_solution = population(1, :);

% 绘制测线
draw_lines(best_solution, length, width);

% 输出测线
disp(best_solution);

以下是辅助函数的实现:

function population = generate_population(population_size, length, width)
    % 生成初始种群
    population = randi([0, 1], population_size, length*width);
end

function fitness = compute_fitness(population, center_depth, slope, beam_width)
    % 计算适应度
    fitness = zeros(size(population, 1), 1);
    for i = 1:size(population, 1)
        solution = population(i, :);
        lines = decode_solution(solution);
        overlap_rate = compute_overlap_rate(lines);
        fitness(i) = abs(center_depth - compute_avg_depth(lines)) + abs(slope - compute_slope(lines)) + abs(overlap_rate - 0.15);
    end
end

function lines = decode_solution(solution)
    % 解码测线
    lines = reshape(solution, 4, 2)';
end

function overlap_rate = compute_overlap_rate(lines)
    % 计算重叠率
    overlap_area = 0;
    for i = 1:size(lines, 1)-1
        overlap_area = overlap_area + compute_overlap_area(lines(i,:), lines(i+1,:));
    end
    total_area = (lines(end, 2) - lines(1, 2)) * 2;
    overlap_rate = overlap_area / total_area;
end

function overlap_area = compute_overlap_area(line1, line2)
    % 计算两条线段之间的重叠面积
    x_overlap = min(line1(2), line2(2)) - max(line1(1), line2(1));
    if x_overlap < 0
        overlap_area = 0;
    else
        overlap_area = x_overlap * (line1(2) - line1(1));
    end
end

function avg_depth = compute_avg_depth(lines)
    % 计算平均深度
    total_depth = 0;
    for i = 1:size(lines, 1)
        total_depth = total_depth + compute_line_depth(lines(i,:));
    end
    avg_depth = total_depth / size(lines, 1);
end

function depth = compute_line_depth(line)
    % 计算线段的平均深度
    depth = (line(2) - line(1)) / 2;
end

function slope = compute_slope(lines)
    % 计算坡度
    depth_diff = 0;
    length_diff = 0;
    for i = 1:size(lines, 1)
        depth_diff = depth_diff + compute_line_depth(lines(i,:));
        length_diff = length_diff + (lines(i,2) - lines(i,1));
    end
    slope = depth_diff / length_diff;
end

function selected_population = selection(population, fitness)
    % 选择操作
    [~, index] = sort(fitness);
    selected_population = population(index(1:ceil(size(population, 1)/2)), :);
end

function new_population = crossover(selected_population, population_size)
    % 交叉操作
    new_population = zeros(population_size, size(selected_population, 2));
    for i = 1:population_size
        parent1 = selected_population(randi(size(selected_population, 1)), :);
        parent2 = selected_population(randi(size(selected_population, 1)), :);
        cross_point = randi(size(parent1));
        new_population(i, :) = [parent1(1:cross_point), parent2(cross_point+1:end)];
    end
end

function population = mutation(new_population)
    % 变异操作
    population = new_population;
    for i = 1:size(population, 1)
        if rand < 0.01 % 变异概率为0.01
            mutation_point = randi(size(population, 2));
            population(i, mutation_point) = 1 - population(i, mutation_point);
        end
    end
end

function draw_lines(solution, length, width)
    % 绘制测线
    lines = decode_solution(solution);
    figure;
    hold on;
    for i = 1:size(lines, 1)
        plot([lines(i, 1), lines(i, 1)], [0, width], 'r');
        plot([lines(i, 2), lines(i, 2)], [0, width], 'r');
        plot([lines(i, 1), lines(i, 2)], [width/2, width/2], 'b');
    end
    xlim([0, length]);
    ylim([0, width]);
    hold off;
end

运行上述代码即可求解该题,并绘制符合要求的一组测线,并输出这组测线。

考虑一个南北长 2 海里、东西宽 4 海里的矩形海域内海域中心点处的海水深度为 110 m西深东浅坡度为 15∘多波束换能器的开角为 120∘。请设计一组测量长度最短、可完全覆盖整个待测海域的测线且相邻条带之间的重叠率满足 10~20 的要求。请用遗传算法求解该题并给出MATLAB代码和绘制符合要求的一组测线并输出这组测线

原文地址: https://www.cveoy.top/t/topic/i3gv 著作权归作者所有。请勿转载和采集!

免费AI点我,无需注册和登录