考虑一个南北长 2 海里、东西宽 4 海里的矩形海域内海域中心点处的海水深度为 110 m西深东浅坡度为 15∘多波束换能器的开角为 120∘。请设计一组测量长度最短、可完全覆盖整个待测海域的测线且相邻条带之间的重叠率满足 10~20 的要求。请用遗传算法求解该题给出Python代码和这组测线结果和绘制测线路径
下面是使用遗传算法求解该问题的Python代码:
import random
import numpy as np
import matplotlib.pyplot as plt
# 海域尺寸
length = 2
width = 4
# 海水深度
depth = 110
# 坡度
slope = 1.5
# 开角
beam_angle = 120
# 目标函数:测线长度最短且满足重叠率要求
def objective_function(chromosome):
lines = decode_chromosome(chromosome)
total_length = sum([line_length(line) for line in lines])
overlap_rate = calculate_overlap_rate(lines)
return total_length + penalty(overlap_rate)
# 解码染色体
def decode_chromosome(chromosome):
lines = []
for i in range(len(chromosome)):
start = i * length / len(chromosome)
end = (i+1) * length / len(chromosome)
line = (start, end, chromosome[i])
lines.append(line)
return lines
# 计算测线长度
def line_length(line):
start, end, angle = line
return np.sqrt((end - start)**2 + (width*np.tan(np.deg2rad(angle)))**2)
# 计算重叠率
def calculate_overlap_rate(lines):
total_overlap = 0
for i in range(len(lines)-1):
overlap = min(lines[i][1], lines[i+1][0]) - max(lines[i][0], lines[i+1][0])
total_overlap += overlap
return total_overlap / (length * (len(lines)-1))
# 惩罚函数
def penalty(overlap_rate):
if overlap_rate < 0.1:
return 100
elif overlap_rate > 0.2:
return 100
else:
return 0
# 生成初始种群
def generate_population(population_size, chromosome_length):
population = []
for _ in range(population_size):
chromosome = [random.randint(0, beam_angle) for _ in range(chromosome_length)]
population.append(chromosome)
return population
# 选择操作
def selection(population, fitness):
total_fitness = sum(fitness)
probabilities = [f/total_fitness for f in fitness]
selected_indices = np.random.choice(range(len(population)), size=len(population), p=probabilities)
return [population[i] for i in selected_indices]
# 交叉操作
def crossover(parent1, parent2):
crossover_point = random.randint(1, len(parent1)-1)
child1 = parent1[:crossover_point] + parent2[crossover_point:]
child2 = parent2[:crossover_point] + parent1[crossover_point:]
return child1, child2
# 变异操作
def mutation(chromosome, mutation_rate):
for i in range(len(chromosome)):
if random.random() < mutation_rate:
chromosome[i] = random.randint(0, beam_angle)
return chromosome
# 遗传算法主函数
def genetic_algorithm(population_size, chromosome_length, generations, mutation_rate):
population = generate_population(population_size, chromosome_length)
best_fitness = float('inf')
best_solution = None
fitness_history = []
for _ in range(generations):
fitness = [objective_function(chromosome) for chromosome in population]
best_index = np.argmin(fitness)
if fitness[best_index] < best_fitness:
best_fitness = fitness[best_index]
best_solution = population[best_index]
fitness_history.append(best_fitness)
parents = selection(population, fitness)
new_population = []
while len(new_population) < population_size:
parent1 = random.choice(parents)
parent2 = random.choice(parents)
child1, child2 = crossover(parent1, parent2)
child1 = mutation(child1, mutation_rate)
child2 = mutation(child2, mutation_rate)
new_population.append(child1)
new_population.append(child2)
population = new_population
return best_solution, best_fitness, fitness_history
# 运行遗传算法
population_size = 100
chromosome_length = 10
generations = 100
mutation_rate = 0.01
best_solution, best_fitness, fitness_history = genetic_algorithm(population_size, chromosome_length, generations, mutation_rate)
# 绘制测线路径
lines = decode_chromosome(best_solution)
x = []
y = []
for line in lines:
start, end, angle = line
x.append(start)
x.append(end)
y.append(width)
y.append(width - width*np.tan(np.deg2rad(angle)))
plt.plot(x, y)
plt.xlabel('Length (nm)')
plt.ylabel('Width (nm)')
plt.title('Survey Line Path')
plt.show()
print('Best Solution:', best_solution)
print('Best Fitness:', best_fitness)
运行代码后,会输出最佳解(测线角度序列)、最佳适应度和适应度历史,并绘制测线路径图。
原文地址: https://www.cveoy.top/t/topic/i3g3 著作权归作者所有。请勿转载和采集!