已知a = 1 1 1 1 1 1 -1 -1 1 -1 1 -1 1 -1 -1 1求1 +1i a; a; a; -a; -a; a; -a; -a; a; a; a; -a; a; -a; a; aresult = for i in rangelena_repeated resultappend1 + 1j a_repeatedi -1 i

a_repeated = a + a + a + (-a) + (-a) + a + (-a) + (-a) + a + a + a + (-a) + a + (-a) + a + a result = [] for i in range(len(a_repeated)): result.append((1 + 1j) * a_repeated[i] * (-1) ** i)

print(result)