可以使用 Panda3D 的 CollisionNode 和 CollisionBox 来实现获取模型的最小值和最大值,以及将模型分成若干个长方体区块。

首先,导入必要的模块:

from panda3d.core import CollisionNode, CollisionBox

然后,加载模型并获取其最小值和最大值:

model = loader.loadModel('path_to_your_model')
model.reparentTo(render)

min_point, max_point = model.getTightBounds()

接下来,计算每个区块的尺寸和数量:

num_blocks_x = 10
num_blocks_y = 10
num_blocks_z = int(max_point.getZ())  # 取模型最高点作为Z轴方向的区块数量

block_size_x = (max_point.getX() - min_point.getX()) / num_blocks_x
block_size_y = (max_point.getY() - min_point.getY()) / num_blocks_y
block_size_z = (max_point.getZ() - min_point.getZ()) / num_blocks_z

然后,创建一个字典用于保存每个区块的最小值和最大值:

blocks = {}

接下来,使用循环来计算每个区块的最小值和最大值,并将其保存到字典中:

for i in range(num_blocks_x):
    for j in range(num_blocks_y):
        for k in range(num_blocks_z):
            min_x = min_point.getX() + i * block_size_x
            max_x = min_point.getX() + (i + 1) * block_size_x

            min_y = min_point.getY() + j * block_size_y
            max_y = min_point.getY() + (j + 1) * block_size_y

            min_z = min_point.getZ() + k * block_size_z
            max_z = min_point.getZ() + (k + 1) * block_size_z

            block_id = i * num_blocks_y * num_blocks_z + j * num_blocks_z + k
            blocks[block_id] = (min_x, max_x, min_y, max_y, min_z, max_z)

最后,得到的 blocks 字典中的键为第多少个区块,值为包含最小最大值的元组。

完整的代码如下所示:

from panda3d.core import CollisionNode, CollisionBox

model = loader.loadModel('path_to_your_model')
model.reparentTo(render)

min_point, max_point = model.getTightBounds()

num_blocks_x = 10
num_blocks_y = 10
num_blocks_z = int(max_point.getZ())

block_size_x = (max_point.getX() - min_point.getX()) / num_blocks_x
block_size_y = (max_point.getY() - min_point.getY()) / num_blocks_y
block_size_z = (max_point.getZ() - min_point.getZ()) / num_blocks_z

blocks = {}

for i in range(num_blocks_x):
    for j in range(num_blocks_y):
        for k in range(num_blocks_z):
            min_x = min_point.getX() + i * block_size_x
            max_x = min_point.getX() + (i + 1) * block_size_x

            min_y = min_point.getY() + j * block_size_y
            max_y = min_point.getY() + (j + 1) * block_size_y

            min_z = min_point.getZ() + k * block_size_z
            max_z = min_point.getZ() + (k + 1) * block_size_z

            block_id = i * num_blocks_y * num_blocks_z + j * num_blocks_z + k
            blocks[block_id] = (min_x, max_x, min_y, max_y, min_z, max_z)

请注意,上述代码假设模型的原点位于其底部中心,如果模型的原点不在底部中心,则需要根据模型的原点位置进行适当的调整。另外,还可以根据实际需求对代码进行适当的修改和优化。

Panda3D 模型分割:获取模型最小值、最大值并划分长方体区块

原文地址: https://www.cveoy.top/t/topic/hrIt 著作权归作者所有。请勿转载和采集!

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