python实现将json： adcode 110000 name 北京市 center 116407387 39904179 level province parent CN children 110101 110102 110105 110106 110107 110108 110109 110111 1101

可以使用Python的json库来实现这个功能。首先，将原始的json数据转换为Python对象，然后提取需要的字段，并重新构建新的json数据。

下面是具体的实现代码：

import json

# 原始的json数据
json_str = '''
[
    {
        "adcode": "110000",
        "name": "北京市",
        "center": [116.407387, 39.904179],
        "level": "province",
        "parent": "CN",
        "children": ["110101", "110102", "110105", "110106", "110107", "110108", "110109", "110111", "110112", "110113", "110114", "110115", "110116", "110117", "110118", "110119"],
        "bbox": [115.423411, 39.442758, 117.514625, 41.060816]
    },
    {
        "adcode": "110101",
        "name": "东城区",
        "center": [116.416334, 39.928359],
        "level": "district",
        "parent": "110000",
        "children": [],
        "bbox": [116.377134, 39.858625, 116.452391, 39.974036]
    }
]
'''

# 将json字符串转换为Python对象
data = json.loads(json_str)

# 提取需要的字段，并重新构建新的json数据
result = []
for item in data:
    result.append({
        "name": item["name"],
        "lnglat": item["center"]
    })

# 将结果转换为json字符串
result_json = json.dumps(result, ensure_ascii=False, indent=4)
print(result_json)

输出结果：

[
    {
        "name": "北京市",
        "lnglat": [
            116.407387,
            39.904179
        ]
    },
    {
        "name": "东城区",
        "lnglat": [
            116.416334,
            39.928359
        ]
    }
]
``