C++代码实现 破译摩斯密码

以下是一个简单的C++代码实现破译摩斯密码的例子：

#include <iostream>
#include <string>
#include <map>

using namespace std;

map<string, char> morseCode = {
    {".-", 'A'}, {"-...", 'B'}, {"-.-.", 'C'}, {"-..", 'D'}, {".", 'E'},
    {"..-.", 'F'}, {"--.", 'G'}, {"....", 'H'}, {"..", 'I'}, {".---", 'J'},
    {"-.-", 'K'}, {".-..", 'L'}, {"--", 'M'}, {"-.", 'N'}, {"---", 'O'},
    {".--.", 'P'}, {"--.-", 'Q'}, {".-.", 'R'}, {"...", 'S'}, {"-", 'T'},
    {"..-", 'U'}, {"...-", 'V'}, {".--", 'W'}, {"-..-", 'X'}, {"-.--", 'Y'},
    {"--..", 'Z'}, {".----", '1'}, {"..---", '2'}, {"...--", '3'}, {"....-", '4'},
    {".....", '5'}, {"-....", '6'}, {"--...", '7'}, {"---..", '8'}, {"----.", '9'},
    {"-----", '0'}
};

string decodeMorseCode(string morseCodeString) {
    string decodedString = "";
    string currentMorseCharacter = "";
    
    for (int i = 0; i < morseCodeString.length(); i++) {
        if (morseCodeString[i] == ' ' && currentMorseCharacter != "") {
            decodedString += morseCode[currentMorseCharacter];
            currentMorseCharacter = "";
        } else if (morseCodeString[i] != ' ') {
            currentMorseCharacter += morseCodeString[i];
        }
    }
    
    if (currentMorseCharacter != "") {
        decodedString += morseCode[currentMorseCharacter];
    }
    
    return decodedString;
}

int main() {
    string morseCodeString = "... --- ... / .-. ..- -.-. .... / ..-. --- .-. / - .... . / .-.. .. -.- . / - --- / .- -. -.. / .. -. -.-. .- .-.. .. -.- .";
    string decodedString = decodeMorseCode(morseCodeString);
    
    cout << "Decoded string: " << decodedString << endl;
    
    return 0;
}

这个例子中，我们使用了一个map数据结构来存储摩斯密码和对应的字母或数字。然后，我们定义了一个decodeMorseCode函数，该函数接受摩斯密码字符串作为参数，并返回解码后的字符串。在函数中，我们通过遍历摩斯密码字符串并逐个字符地处理，将摩斯密码字符转换为对应的字母或数字。最后，在main函数中，我们定义了一个摩斯密码字符串，并使用decodeMorseCode函数解码它，并将结果打印到控制台上