c++写程序：一个合法的身份证号码由17位地区、日期编号和顺序编号加1位校验码组成。校验码的计算规则如下：首先对前17位数字加权求和权重分配为：7910584216379105842；然后将计算的和对11取模得到值Z；最后按照以下关系对应Z值与校验码M的值：Z：0 1 2 3 4 5 6 7 8 9 10M：1 0 X 9 8 7 6 5 4 3 2现在给定一些身份证号码请你验证校验码的有效性并输

#include <iostream>
#include <string>
using namespace std;

int main() {
    int N;
    cin >> N;
    string id[N];
    for (int i = 0; i < N; i++) {
        cin >> id[i];
    }
    
    string M = "10X98765432";
    bool allPassed = true;
    for (int i = 0; i < N; i++) {
        string s = id[i];
        int sum = 0;
        for (int j = 0; j < 17; j++) {
            if (s[j] >= '0' && s[j] <= '9') {
                sum += (s[j] - '0') * (7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2)[j];
            } else {
                allPassed = false;
                cout << s << endl;
                break;
            }
        }
        if (allPassed) {
            int Z = sum % 11;
            if (s[17] != M[Z]) {
                allPassed = false;
                cout << s << endl;
            }
        }
    }
    
    if (allPassed) {
        cout << "All passed" << endl;
    }
    
    return 0;
}
``