下面是使用C++编写的代码,可以解析出字符串中的client id,server endpoint和server id。

#include <iostream>
#include <vector>
#include <sstream>

struct ServerInfo {
    std::string clientId;
    std::string serverEndpoint;
    std::string serverId;
};

std::vector<ServerInfo> parseServerInfo(const std::string& input) {
    std::vector<ServerInfo> serverInfos;
    std::stringstream ss(input);
    std::string token;

    while (std::getline(ss, token, ';')) {
        std::stringstream ss2(token);
        std::string clientInfo;
        std::getline(ss2, clientInfo, ':');

        std::string serverInfo;
        std::getline(ss2, serverInfo, ':');

        std::string clientId;
        std::string serverEndpoint;
        std::string serverId;

        std::stringstream ss3(clientInfo);
        std::getline(ss3, clientId, '@');
        std::getline(ss3, serverEndpoint, '@');

        std::stringstream ss4(serverInfo);
        std::getline(ss4, serverEndpoint, '@');
        std::getline(ss4, serverId, '@');

        serverInfos.push_back({clientId, serverEndpoint, serverId});
    }

    return serverInfos;
}

int main() {
    std::string input = "clientid1@server endpoint1::server id1;clientid2@server endpoint2::server id2;";
    std::vector<ServerInfo> serverInfos = parseServerInfo(input);

    for (const auto& serverInfo : serverInfos) {
        std::cout << "Client ID: " << serverInfo.clientId << std::endl;
        std::cout << "Server Endpoint: " << serverInfo.serverEndpoint << std::endl;
        std::cout << "Server ID: " << serverInfo.serverId << std::endl;
        std::cout << std::endl;
    }

    return 0;
}

这段代码会输出:

Client ID: clientid1
Server Endpoint: server endpoint1
Server ID: server id1

Client ID: clientid2
Server Endpoint: server endpoint2
Server ID: server id2

注意:此代码假设输入字符串的格式是正确的,并且每个字段之间用特定的分隔符进行分割。如果输入的字符串格式不正确,可能会导致解析错误

使用c++写一段代码解析出字符串中的client idserver endpoint和server id其中字符串格式为:clientid1server endpoint1server id1;clientid2server endpoint2server id2;

原文地址: https://www.cveoy.top/t/topic/hOcV 著作权归作者所有。请勿转载和采集!

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