Synthetic Division: Finding the Quotient and Remainder of (-xᄇ + x - 5) / (x + 1)
Synthetic Division: Dividing -xᄇ + x - 5 by x + 1
Synthetic division is a shortcut method to divide polynomials, particularly useful when the divisor is a linear expression like x + 1. Here's how to find the quotient and remainder of (-xᄇ + x - 5) / (x + 1) using synthetic division:
1. Set up the Division:
- Write the coefficients of the dividend (-xᄇ + x - 5) in a row: -1 1 -5
- Write the opposite of the constant term of the divisor (x + 1) to the left: -1
This setup looks like this:
-1 | -1 1 -5
2. Bring Down the First Coefficient:
Bring down the first coefficient (-1) below the line.
-1 | -1 1 -5
| -1
|--------
3. Multiply and Add:
- Multiply the divisor (-1) by the number you just brought down (-1): (-1) * (-1) = 1
- Write the result (1) in the next column.
- Add the numbers in that column: 1 + 1 = 2
-1 | -1 1 -5
| -1 1
|--------
-1 2
4. Repeat the Process:
- Multiply the divisor (-1) by the new number below the line (2): (-1) * 2 = -2
- Write the result (-2) in the next column.
- Add the numbers in that column: -2 + (-5) = -7
-1 | -1 1 -5
| -1 1 -2
|--------
-1 2 -7
5. Interpret the Results:
- The numbers below the line (-1, 2) are the coefficients of the quotient, starting with one degree less than the dividend. In this case, the quotient is -x + 2.
- The last number below the line (-7) is the remainder.
Therefore, (-xᄇ + x - 5) / (x + 1) = -x + 2 - 7/(x + 1).
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