以下是一个用Python编写的9x9数独游戏:

def print_board(board):
    for i in range(len(board)):
        if i % 3 == 0 and i != 0:
            print("- - - - - - - - - - - - - -")
        for j in range(len(board[0])):
            if j % 3 == 0 and j != 0:
                print(" | ", end="")
            if j == 8:
                print(board[i][j])
            else:
                print(str(board[i][j]) + " ", end="")

def find_empty(board):
    for i in range(len(board)):
        for j in range(len(board[0])):
            if board[i][j] == 0:
                return (i, j)
    return None

def valid(board, num, pos):
    # 检查行
    for i in range(len(board[0])):
        if board[pos[0]][i] == num and pos[1] != i:
            return False

    # 检查列
    for i in range(len(board)):
        if board[i][pos[1]] == num and pos[0] != i:
            return False

    # 检查九宫格
    box_x = pos[1] // 3
    box_y = pos[0] // 3

    for i in range(box_y * 3, box_y * 3 + 3):
        for j in range(box_x * 3, box_x * 3 + 3):
            if board[i][j] == num and (i, j) != pos:
                return False

    return True

def solve(board):
    find = find_empty(board)
    if not find:
        return True
    else:
        row, col = find

    for i in range(1, 10):
        if valid(board, i, (row, col)):
            board[row][col] = i

            if solve(board):
                return True

            board[row][col] = 0

    return False

# 数独游戏的初始数独板
board = [
    [5, 3, 0, 0, 7, 0, 0, 0, 0],
    [6, 0, 0, 1, 9, 5, 0, 0, 0],
    [0, 9, 8, 0, 0, 0, 0, 6, 0],
    [8, 0, 0, 0, 6, 0, 0, 0, 3],
    [4, 0, 0, 8, 0, 3, 0, 0, 1],
    [7, 0, 0, 0, 2, 0, 0, 0, 6],
    [0, 6, 0, 0, 0, 0, 2, 8, 0],
    [0, 0, 0, 4, 1, 9, 0, 0, 5],
    [0, 0, 0, 0, 8, 0, 0, 7, 9]
]

print("初始数独板:")
print_board(board)
solve(board)
print("\n解决数独板:")
print_board(board)

运行上述代码,将会打印出初始的数独板和解决后的数独板

用Python语言编写一个99的数列游戏

原文地址: https://www.cveoy.top/t/topic/hBkr 著作权归作者所有。请勿转载和采集!

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