Walk Alone planted nnn magical carrot trees in a row Let aia_iai denote the number of carrots on the iii-th tree note that aia_iai is a real number Initially there are no carrots on any tree On each

Here is a possible implementation in C++:

#include <iostream>
#include <vector>

using namespace std;

int main() {
    int n, m, k;
    cin >> n >> m >> k;
    
    vector<double> carrots(n+1, 0);
    
    for (int i = 0; i < m; i++) {
        int type, l, r, x;
        cin >> type >> l >> r;
        
        if (type == 1) {
            cin >> x;
            for (int j = l; j <= r; j++) {
                carrots[j] += x/k;
            }
        } else {
            for (int j = l; j <= r; j++) {
                if (carrots[j] >= 1) {
                    carrots[j] -= 1;
                }
            }
        }
    }
    
    int totalCarrots = 0;
    for (int i = 1; i <= n; i++) {
        totalCarrots += (int)carrots[i];
    }
    
    cout << totalCarrots << endl;
    
    return 0;
}

Explanation:

• We start by reading the input values for n, m, and k.
• We create a vector carrots of size n+1 to store the number of carrots on each tree. We initialize all elements to 0.
• We iterate m times to process each operation.
• For each operation, we read the type (1 or 2), l, and r. If the type is 1, we also read x.
• If the type is 1, we iterate from l to r and increase the number of carrots on each tree by x/k.
• If the type is 2, we iterate from l to r and decrease the number of carrots on each tree by 1 if the current number of carrots is at least 1.
• After processing all operations, we calculate the total number of carrots by summing up the integer part of each element in the carrots vector.
• Finally, we output the total number of carrots