这串Python代码扩张一个UI界面:def count_virus_filespath virus_count = 0 if ospathexistspath if ospathisdirpath files = oslistdirpath for file in files file_path
完整的代码如下所示:
import os
def is_virus(file_path):
# 判断文件是否为病毒文件的逻辑
pass
def scan_directory(path):
# 扫描目录并打印文件路径的逻辑
pass
def quarantine_virus_files(path):
# 隔离病毒文件到隔离目录的逻辑
pass
def clean_quarantine_directory():
# 清理隔离目录的逻辑
pass
def count_virus_files(path):
virus_count = 0
if os.path.exists(path):
if os.path.isdir(path):
files = os.listdir(path)
for file in files:
file_path = os.path.join(path, file)
if os.path.isfile(file_path):
if is_virus(file_path):
virus_count += 1
elif os.path.isdir(file_path):
virus_count += count_virus_files(file_path)
return virus_count
def restore_quarantine_files():
quarantine_path = os.path.join(os.getcwd(), "Quarantine")
if os.path.exists(quarantine_path) and os.path.isdir(quarantine_path):
files = os.listdir(quarantine_path)
for file in files:
file_path = os.path.join(quarantine_path, file)
if os.path.isfile(file_path):
new_path = os.path.join(os.getcwd(), os.path.basename(file_path))
os.rename(file_path, new_path)
print('已经恢复文件:', new_path)
os.rmdir(quarantine_path)
path = input("请输入要扫描的目录:")
action = input("请选择要执行的操作:\n1. 扫描目录并统计病毒文件数量\n2. 隔离病毒文件\n3. 清理隔离目录并恢复文件\n")
if action == '1':
scan_directory(path)
virus_count = count_virus_files(path)
print('共发现', virus_count, '个病毒文件')
elif action == '2':
quarantine_virus_files(path)
print('已经隔离所有病毒文件')
elif action == '3':
clean_quarantine_directory()
print('已经清理隔离目录')
restore_quarantine_files()
print('已经恢复隔离文件到原始目录')
else:
print('无效的操作')
请注意,在添加新函数时,需要根据实际需要实现相应的逻辑。上述代码中的 is_virus、scan_directory、quarantine_virus_files 和 clean_quarantine_directory 函数都是假设已经实现好的函数,并没有给出具体实现。您需要根据实际情况自行编写这些函数的逻辑
原文地址: https://www.cveoy.top/t/topic/h37t 著作权归作者所有。请勿转载和采集!