find dydx for the y=ln3x^2+2x

To find dy/dx for the equation y = ln(3x^2 + 2x), we can use the chain rule.

Let u = 3x^2 + 2x. To find du/dx, we can differentiate u with respect to x: du/dx = d(3x^2 + 2x)/dx = 6x + 2.

Now, let y = ln(u). To find dy/du, we differentiate y with respect to u: dy/du = 1/u.

Finally, using the chain rule, we can find dy/dx: dy/dx = (dy/du) * (du/dx) = (1/u) * (6x + 2) = (6x + 2)/(3x^2 + 2x).

Therefore, dy/dx for the equation y = ln(3x^2 + 2x) is (6x + 2)/(3x^2 + 2x).