SELECT empempid empname hsumdays FROM emp JOIN holiday h on empempid=hempid GROUP BY empid改正

• 日期: 2028-02-06 16:41:23
• 标签: 社会

SELECT emp.empid, emp.name, SUM(h.days) FROM emp JOIN holiday h ON emp.empid = h.empid GROUP BY emp.empid, emp.name

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