i=3;printfdn++i;printfdni++;

The output of the code will be:

4 4

Explanation:

• In the first printf statement, the value of i is incremented by 1 and then printed. So, the output is 4.
• In the second printf statement, the current value of i (which is 4) is printed and then incremented by 1. So, the output is also 4.