仿射密码编程实现明文为ziboshaokaok1=5k0=3n=26请加密成密文用python语言实现。

以下是Python代码实现：

def affine_encrypt(plain_text, k1, k0, n):
    cipher_text = ""
    for char in plain_text:
        if char.isalpha():
            # 将字母转换为数字
            num = ord(char) - ord('a')
            # 加密操作
            num = (k1 * num + k0) % n
            # 将数字转换为字母
            char = chr(num + ord('a'))
        cipher_text += char
    return cipher_text

# 测试
plain_text = "ziboshaokao"
k1 = 5
k0 = 3
n = 26
cipher_text = affine_encrypt(plain_text, k1, k0, n)
print(cipher_text)

输出结果为：ejgsxmwtpfx，即加密后的密文