c语言完成以下任务减少内存使用封装到一个函数：1while语句实现求1+2+……+100的和。2随意输入一个整数n求1—n之间的奇数和和偶数和。3求1+2+3+4……+100的和4求n的阶乘5编程序统计并输出200以内所有能同时被7和3整除的数及其数量。6定义一个数组a10并赋初值0~9反序输出。7一个小组学生共10人输入他们的成绩计算并输出小组总成绩及平均成绩。8封装一个函数并且在主函数中进行调

int sum = 0; int i = 1; while(i <= 100){ sum += i; i++; } printf("1+2+...+100=%d\n", sum);

int n, i, odd_sum = 0, even_sum = 0; scanf("%d", &n); for(i = 1; i <= n; i++){ if(i % 2 == 0){ even_sum += i; } else{ odd_sum += i; } } printf("1 to %d odd sum: %d, even sum: %d\n", n, odd_sum, even_sum);

int sum = 0; int i; for(i = 1; i <= 100; i++){ sum += i; } printf("1+2+...+100=%d\n", sum);

int n, i, factorial = 1; scanf("%d", &n); for(i = 1; i <= n; i++){ factorial *= i; } printf("%d! = %d\n", n, factorial);

int count = 0; int i; for(i = 1; i <= 200; i++){ if(i % 3 == 0 && i % 7 == 0){ printf("%d ", i); count++; } } printf("\nTotal count: %d\n", count);

int a[10] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; int i; for(i = 9; i >= 0; i--){ printf("%d ", a[i]); } printf("\n");

int i, score, total_score = 0; float avg_score; for(i = 1; i <= 10; i++){ scanf("%d", &score); total_score += score; } avg_score = (float)total_score / 10; printf("Total score: %d, Average score: %.2f\n", total_score, avg_score);

int max(int a, int b){ return a > b ? a : b; } int a, b; scanf("%d %d", &a, &b); printf("Max: %d\n", max(a, b));

float cm, inch; scanf("%f", &cm); inch = cm / 2.54; printf("%.2f cm = %.2f inch\n", cm, inch);

int n, i; scanf("%d", &n); for(i = 2; i <= n / 2; i++){ if(n % i == 0){ printf("%d is not a prime number.\n", n); break; } } if(i > n / 2){ printf("%d is a prime number.\n", n); }

char str[100]; scanf("%s", str); int len = strlen(str); int i; for(i = len - 1; i >= 0; i--){ printf("%c", str[i]); } printf("\n");

srand((unsigned)time(NULL)); int nums[5] = {0}; int i, j, num; for(i = 0; i < 5; i++){ while(1){ num = rand() % 100 + 1; for(j = 0; j < i; j++){ if(num == nums[j]){ break; } } if(j == i){ nums[i] = num; break; } } } for(i = 0; i < 5; i++){ printf("%d ", nums[i]); } printf("\n");

char password[9] = "12345678"; char crack[9] = "00000000"; int i, j, k, l, m, n, o, p; for(i = 0; i < 10; i++){ for(j = 0; j < 10; j++){ for(k = 0; k < 10; k++){ for(l = 0; l < 10; l++){ for(m = 0; m < 10; m++){ for(n = 0; n < 10; n++){ for(o = 0; o < 10; o++){ for(p = 0; p < 10; p++){ crack[0] = '0' + i; crack[1] = '0' + j; crack[2] = '0' + k; crack[3] = '0' + l; crack[4] = '0' + m; crack[5] = '0' + n; crack[6] = '0' + o; crack[7] = '0' + p; if(strcmp(password, crack) == 0){ printf("Cracked password: %s\n", crack); return 0; } } } } } } } } } printf("Password not found.\n");

int nums[5] = {5, 81, 65, 9, 10}; int i, j, temp; for(i = 0; i < 5; i++){ for(j = 0; j < 5 - i - 1; j++){ if(nums[j] > nums[j + 1]){ temp = nums[j]; nums[j] = nums[j + 1]; nums[j + 1] = temp; } } } for(i = 0; i < 5; i++){ printf("%d ", nums[i]); } printf("\n")