main int n; n=64n+6n2; printfn=dnn;

The output of this program will be:

n=24

The comma operator is used in the line (n=6*4,n+6),n*2; to separate two expressions. The first expression assigns the value 24 to the variable n and then adds 6 to it, which evaluates to 30 (but is not stored anywhere). The second expression multiplies the value of n (which is still 24) by 2 and does not affect the value of n.

However, since the comma operator has lower precedence than the assignment and arithmetic operators, the expression is actually equivalent to (n=6*4,(n+6),n*2);, which means that the result of (n+6) is calculated but not used. Thus, the value of n remains 24 and is printed as such