int m = 4 n = 15;whilem++ --n;Systemoutprintlnm ++n

The output of this code will be "6 10".

Initially, m is 4 and n is 15. The while loop condition checks if m is less than n, which is true (4 is less than 15).

Inside the loop, m is incremented by 1 (so it becomes 5) and n is decremented by 1 (so it becomes 14).

This process continues until m is equal to n (which would make the loop condition false). At that point, m will be 6 and n will be 10.

The loop will not execute again because the condition m++ < --n will be false when m is 6 and n is 10.

The final output statement prints the values of m and n separated by a space