用c语言写一段完整的求单链表中节点个数的代码。要求有输入与输出

#include <stdio.h> #include <stdlib.h>

typedef struct Node { int data; struct Node* next; } Node;

int countNodes(Node* head) { int count = 0; Node* current = head; while (current != NULL) { count++; current = current->next; } return count; }

void insert(Node** head, int data) { Node* newNode = (Node*)malloc(sizeof(Node)); newNode->data = data; newNode->next = NULL;

if (*head == NULL) {
    *head = newNode;
} else {
    Node* current = *head;
    while (current->next != NULL) {
        current = current->next;
    }
    current->next = newNode;
}

}

void printList(Node* head) { Node* current = head; while (current != NULL) { printf("%d ", current->data); current = current->next; } printf("\n"); }

int main() { Node* head = NULL; int n, data; printf("Enter the number of nodes: "); scanf("%d", &n); printf("Enter the data values:\n"); for (int i = 0; i < n; i++) { scanf("%d", &data); insert(&head, data); } printf("The linked list is: "); printList(head); int count = countNodes(head); printf("The number of nodes in the linked list is: %d\n", count); return 0;